Enter the required reinforcement run, available stock-bar length and lap overlap. The calculator determines the minimum number of bars and splice locations needed to reach the required continuous length under the simple repeated-lap model.
Enter the continuous run.
With n stock bars and a repeated lap of L, the continuous theoretical coverage is n × stock length − (n − 1) × lap length. The calculator finds the smallest integer n whose coverage reaches the required run.
Four 12 m bars with 0.80 m laps provide 48 − 2.40 = 45.60 m of continuous coverage, so four bars are not enough for a 48 m run. A fifth bar provides 56.00 m under the same simple model, creating four splice locations.
The mathematical count does not decide where splices may occur, whether splices can be concentrated in one zone, whether staggering is required, or whether a particular lap length is code-compliant. Those are structural detailing decisions.
| Metric | Meaning |
|---|---|
| Stock bars required | Minimum bars under the repeated-lap arithmetic. |
| Splice locations | One fewer than the number of bars. |
| Gross purchased length | Number of stock bars × stock length. |
| Lap overlap | Splice count × lap length. |
Under this simplified continuous-run model, yes: each connection between adjacent stock bars creates one overlap.
No. It calculates quantity, not the structural location of splice zones.
The inputs are rejected because a repeated overlap cannot physically provide positive new coverage when the lap consumes the entire stock length.