Motor Pump Energy Savings Calculator
Compare the electrical power required by a pump motor before and after a proposed operating or efficiency change. See annual energy use, cost savings and the percentage reduction.
Compare pump operation
Pump energy result
How pump energy savings are calculated
The primary comparison uses the actual electrical power of the baseline and proposed pump conditions. This is intentionally direct: annual energy is power multiplied by operating hours.
Annual energy = Electrical power × Annual operating hours
Annual saving = (Baseline power − Proposed power) × Annual operating hours
The result is multiplied by the electricity price to obtain the annual cost difference.
Why flow is shown separately
A lower pump power is only useful if the required hydraulic service is still delivered. The optional flow fields provide a quick sanity check. A proposed case with materially lower flow may not be a genuine like-for-like energy improvement.
Good inputs
Measured kW from the motor or drive can provide a stronger basis than nameplate assumptions. For a proposed pump change, use a credible pump/system operating point or project estimate.
Limitations
- Hydraulic head is not modeled directly.
- Pump efficiency, motor efficiency and drive efficiency are incorporated only indirectly through the entered electrical power.
- The tool does not verify that a proposed pump can meet required flow and head.
- Energy-price assumptions are user-entered.
FAQs
Can baseline and proposed flow be different?
Yes. The tool reports that difference so you can see whether the savings case changes the delivered hydraulic service.
Does lower kW always mean a better pump?
No. A pump must satisfy the required hydraulic duty.
Can I enter zero flow?
Yes mathematically, but zero-flow conditions may represent a different operating state rather than a valid production comparison.
Does this include demand charges?
No. It models energy cost from kWh only.