What is the mid-span deflection of a W24x55 beam spanning 6.0 meters under 20.0 kN/m?
⚡ Instant Calculated Answer
A W24x55 steel beam across a 6.0 meter span under a 20.0 kN/m uniform distributed load deflects by 3.0 mm at mid-span, which PASSES the standard building code L/360 serviceability limit (16.67 mm).
3.0 mm
Primary Metric
Limit: 16.67 mm
Secondary Metric
📐 Mathematical Formula & Step-by-Step Substitution
- Identify beam properties: Section W24x55, Moment of Inertia I_x = 56,200 cm⁴ (5.6200e-04 m⁴), Young's Modulus E = 200 GPa.
- Convert units: Span L = 6.0 m, Load w = 20.0 kN/m = 20,000 N/m.
- Calculate numerator: 5 × 20,000 × (6.0)⁴ = 5 × 20,000 × 1296.00 = 129,600,000.0.
- Calculate denominator: 384 × 200×10⁹ × 5.6200e-04 = 43,161,600,000.0.
- Evaluate deflection: 129,600,000.0 / 43,161,600,000.0 = 0.00300 m = 3.0 mm (compared to L/360 = 16.67 mm).
📊 Nearby Parameter Reference Table
| Span Length | Uniform Load | Mid-Span Deflection | L/360 Code Limit |
|---|---|---|---|
| 5.0 m | 20.0 kN/m | 1.45 mm | 13.89 mm (OK) |
| 5.5 m | 20.0 kN/m | 2.12 mm | 15.28 mm (OK) |
| 6.0 m | 20.0 kN/m | 3.0 mm | 16.67 mm (OK) |
| 6.5 m | 20.0 kN/m | 4.14 mm | 18.06 mm (OK) |
| 7.0 m | 20.0 kN/m | 5.56 mm | 19.44 mm (OK) |
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