Paleontology & Geochronology

How old is a specimen with 25% Uranium-235 (²³⁵U) remaining?

⚡ Instant Calculated Answer

A specimen containing 25% remaining Uranium-235 (²³⁵U) has an age of exactly 1.408 Ga (representing 2.0 half-lives elapsed since closure).

1.408 Ga Primary Metric
2.0 Half-Lives Secondary Metric

📐 Mathematical Formula & Step-by-Step Substitution

\[ t = -\frac{T_{1/2}}{\ln(2)} \cdot \ln\left(\frac{N(t)}{N_0}\right) = -\frac{703800000}{\ln(2)} \cdot \ln(0.25) = 1.408 Ga \]
t = -(703800000 / ln(2)) * ln(0.25) = 1.408 Ga
  1. Identify the isotope half-life: T_1/2 = 703,800,000 years (703.8 Ma).
  2. Calculate remaining fraction N(t)/N_0 = 25% = 0.25.
  3. Take natural logarithm of fraction: ln(0.25) = -1.38629.
  4. Apply decay constant lambda = ln(2) / T_1/2 = 9.849e-10 yr⁻¹.
  5. Compute age: t = --1.38629 / (9.849e-10) = 1.408 Ga.

📊 Nearby Parameter Reference Table

Isotope Remaining Half-Lives Elapsed Calculated Age
30.0% 1.74 1.222 Ga
27.5% 1.86 1.311 Ga
25.0% 2.0 1.408 Ga
22.5% 2.15 1.515 Ga
20.0% 2.32 1.634 Ga
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