How many troy ounces of fine gold are in 500 grams of 21K gold?
⚡ Instant Calculated Answer
500 grams of 21K gold contains exactly 437.5 grams (14.066 troy ounces) of pure fine gold, with an intrinsic scrap melt value of approximately $37,978.20 USD at $2,700/oz t.
14.066 oz t
Primary Metric
437.5 g Fine Au
Secondary Metric
📐 Mathematical Formula & Step-by-Step Substitution
- Determine fineness ratio of 21K gold: 21 / 24 = 0.8750 (or 875.0‰ millesimal fineness).
- Multiply gross weight by fineness: 500 g × 0.8750 = 437.5 grams of fine elemental gold (Au).
- Convert grams to troy ounces (1 oz t = 31.1034768 g): 437.5 / 31.1034768 = 14.066 troy ounces.
- Convert grams to tolas (1 tola = 11.6638 g): 437.5 / 11.6638 = 37.5092 tolas.
📊 Nearby Parameter Reference Table
| Gross Weight | Fine Gold (g) | Fine Gold (oz t) | Melt Value ($2,700/oz) |
|---|---|---|---|
| 250 g | 218.75 g | 7.033 oz t | $18,989.10 |
| 400 g | 350.0 g | 11.2528 oz t | $30,382.56 |
| 500 g | 437.5 g | 14.066 oz t | $37,978.20 |
| 600 g | 525.0 g | 16.8791 oz t | $45,573.57 |
| 750 g | 656.25 g | 21.0989 oz t | $56,967.03 |
| 1000 g | 875.0 g | 28.1319 oz t | $75,956.13 |
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