How many troy ounces of fine gold are in 5 grams of 24K gold?
⚡ Instant Calculated Answer
5 grams of 24K gold contains exactly 5.0 grams (0.1608 troy ounces) of pure fine gold, with an intrinsic scrap melt value of approximately $434.16 USD at $2,700/oz t.
0.1608 oz t
Primary Metric
5.0 g Fine Au
Secondary Metric
📐 Mathematical Formula & Step-by-Step Substitution
- Determine fineness ratio of 24K gold: 24 / 24 = 0.9999 (or 999.9‰ millesimal fineness).
- Multiply gross weight by fineness: 5 g × 0.9999 = 5.0 grams of fine elemental gold (Au).
- Convert grams to troy ounces (1 oz t = 31.1034768 g): 5.0 / 31.1034768 = 0.1608 troy ounces.
- Convert grams to tolas (1 tola = 11.6638 g): 5.0 / 11.6638 = 0.4287 tolas.
📊 Nearby Parameter Reference Table
| Gross Weight | Fine Gold (g) | Fine Gold (oz t) | Melt Value ($2,700/oz) |
|---|---|---|---|
| 2.5 g | 2.5 g | 0.0804 oz t | $217.08 |
| 4 g | 4.0 g | 0.1286 oz t | $347.22 |
| 5 g | 5.0 g | 0.1608 oz t | $434.16 |
| 6 g | 5.999 g | 0.1929 oz t | $520.83 |
| 7.5 g | 7.499 g | 0.2411 oz t | $650.97 |
| 10 g | 9.999 g | 0.3215 oz t | $868.05 |
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