How many troy ounces of fine gold are in 5 grams of 21K gold?
⚡ Instant Calculated Answer
5 grams of 21K gold contains exactly 4.375 grams (0.1407 troy ounces) of pure fine gold, with an intrinsic scrap melt value of approximately $379.89 USD at $2,700/oz t.
0.1407 oz t
Primary Metric
4.375 g Fine Au
Secondary Metric
📐 Mathematical Formula & Step-by-Step Substitution
- Determine fineness ratio of 21K gold: 21 / 24 = 0.8750 (or 875.0‰ millesimal fineness).
- Multiply gross weight by fineness: 5 g × 0.8750 = 4.375 grams of fine elemental gold (Au).
- Convert grams to troy ounces (1 oz t = 31.1034768 g): 4.375 / 31.1034768 = 0.1407 troy ounces.
- Convert grams to tolas (1 tola = 11.6638 g): 4.375 / 11.6638 = 0.3751 tolas.
📊 Nearby Parameter Reference Table
| Gross Weight | Fine Gold (g) | Fine Gold (oz t) | Melt Value ($2,700/oz) |
|---|---|---|---|
| 2.5 g | 2.188 g | 0.0703 oz t | $189.81 |
| 4 g | 3.5 g | 0.1125 oz t | $303.75 |
| 5 g | 4.375 g | 0.1407 oz t | $379.89 |
| 6 g | 5.25 g | 0.1688 oz t | $455.76 |
| 7.5 g | 6.562 g | 0.211 oz t | $569.70 |
| 10 g | 8.75 g | 0.2813 oz t | $759.51 |
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