How many troy ounces of fine gold are in 5 grams of 14K gold?
⚡ Instant Calculated Answer
5 grams of 14K gold contains exactly 2.917 grams (0.0938 troy ounces) of pure fine gold, with an intrinsic scrap melt value of approximately $253.26 USD at $2,700/oz t.
0.0938 oz t
Primary Metric
2.917 g Fine Au
Secondary Metric
📐 Mathematical Formula & Step-by-Step Substitution
- Determine fineness ratio of 14K gold: 14 / 24 = 0.5833 (or 583.3‰ millesimal fineness).
- Multiply gross weight by fineness: 5 g × 0.5833 = 2.917 grams of fine elemental gold (Au).
- Convert grams to troy ounces (1 oz t = 31.1034768 g): 2.917 / 31.1034768 = 0.0938 troy ounces.
- Convert grams to tolas (1 tola = 11.6638 g): 2.917 / 11.6638 = 0.2501 tolas.
📊 Nearby Parameter Reference Table
| Gross Weight | Fine Gold (g) | Fine Gold (oz t) | Melt Value ($2,700/oz) |
|---|---|---|---|
| 2.5 g | 1.458 g | 0.0469 oz t | $126.63 |
| 4 g | 2.333 g | 0.075 oz t | $202.50 |
| 5 g | 2.917 g | 0.0938 oz t | $253.26 |
| 6 g | 3.5 g | 0.1125 oz t | $303.75 |
| 7.5 g | 4.375 g | 0.1407 oz t | $379.89 |
| 10 g | 5.833 g | 0.1875 oz t | $506.25 |
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