How many troy ounces of fine gold are in 5 grams of 10K gold?
⚡ Instant Calculated Answer
5 grams of 10K gold contains exactly 2.083 grams (0.067 troy ounces) of pure fine gold, with an intrinsic scrap melt value of approximately $180.90 USD at $2,700/oz t.
0.067 oz t
Primary Metric
2.083 g Fine Au
Secondary Metric
📐 Mathematical Formula & Step-by-Step Substitution
- Determine fineness ratio of 10K gold: 10 / 24 = 0.4167 (or 416.7‰ millesimal fineness).
- Multiply gross weight by fineness: 5 g × 0.4167 = 2.083 grams of fine elemental gold (Au).
- Convert grams to troy ounces (1 oz t = 31.1034768 g): 2.083 / 31.1034768 = 0.067 troy ounces.
- Convert grams to tolas (1 tola = 11.6638 g): 2.083 / 11.6638 = 0.1786 tolas.
📊 Nearby Parameter Reference Table
| Gross Weight | Fine Gold (g) | Fine Gold (oz t) | Melt Value ($2,700/oz) |
|---|---|---|---|
| 2.5 g | 1.042 g | 0.0335 oz t | $90.45 |
| 4 g | 1.667 g | 0.0536 oz t | $144.72 |
| 5 g | 2.083 g | 0.067 oz t | $180.90 |
| 6 g | 2.5 g | 0.0804 oz t | $217.08 |
| 7.5 g | 3.125 g | 0.1005 oz t | $271.35 |
| 10 g | 4.167 g | 0.134 oz t | $361.80 |
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