How many troy ounces of fine gold are in 31.1035 grams of 21K gold?
⚡ Instant Calculated Answer
31.1035 grams of 21K gold contains exactly 27.216 grams (0.875 troy ounces) of pure fine gold, with an intrinsic scrap melt value of approximately $2,362.50 USD at $2,700/oz t.
0.875 oz t
Primary Metric
27.216 g Fine Au
Secondary Metric
📐 Mathematical Formula & Step-by-Step Substitution
- Determine fineness ratio of 21K gold: 21 / 24 = 0.8750 (or 875.0‰ millesimal fineness).
- Multiply gross weight by fineness: 31.1035 g × 0.8750 = 27.216 grams of fine elemental gold (Au).
- Convert grams to troy ounces (1 oz t = 31.1034768 g): 27.216 / 31.1034768 = 0.875 troy ounces.
- Convert grams to tolas (1 tola = 11.6638 g): 27.216 / 11.6638 = 2.3334 tolas.
📊 Nearby Parameter Reference Table
| Gross Weight | Fine Gold (g) | Fine Gold (oz t) | Melt Value ($2,700/oz) |
|---|---|---|---|
| 15.55 g | 13.606 g | 0.4374 oz t | $1,180.98 |
| 24.88 g | 21.77 g | 0.6999 oz t | $1,889.73 |
| 31.1 g | 27.213 g | 0.8749 oz t | $2,362.23 |
| 37.32 g | 32.655 g | 1.0499 oz t | $2,834.73 |
| 46.66 g | 40.828 g | 1.3127 oz t | $3,544.29 |
| 62.21 g | 54.434 g | 1.7501 oz t | $4,725.27 |
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