How many troy ounces of fine gold are in 31.1035 grams of 10K gold?
⚡ Instant Calculated Answer
31.1035 grams of 10K gold contains exactly 12.96 grams (0.4167 troy ounces) of pure fine gold, with an intrinsic scrap melt value of approximately $1,125.09 USD at $2,700/oz t.
0.4167 oz t
Primary Metric
12.96 g Fine Au
Secondary Metric
📐 Mathematical Formula & Step-by-Step Substitution
- Determine fineness ratio of 10K gold: 10 / 24 = 0.4167 (or 416.7‰ millesimal fineness).
- Multiply gross weight by fineness: 31.1035 g × 0.4167 = 12.96 grams of fine elemental gold (Au).
- Convert grams to troy ounces (1 oz t = 31.1034768 g): 12.96 / 31.1034768 = 0.4167 troy ounces.
- Convert grams to tolas (1 tola = 11.6638 g): 12.96 / 11.6638 = 1.1111 tolas.
📊 Nearby Parameter Reference Table
| Gross Weight | Fine Gold (g) | Fine Gold (oz t) | Melt Value ($2,700/oz) |
|---|---|---|---|
| 15.55 g | 6.479 g | 0.2083 oz t | $562.41 |
| 24.88 g | 10.367 g | 0.3333 oz t | $899.91 |
| 31.1 g | 12.958 g | 0.4166 oz t | $1,124.82 |
| 37.32 g | 15.55 g | 0.4999 oz t | $1,349.73 |
| 46.66 g | 19.442 g | 0.6251 oz t | $1,687.77 |
| 62.21 g | 25.921 g | 0.8334 oz t | $2,250.18 |
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