How many troy ounces of fine gold are in 200 grams of 18K gold?
⚡ Instant Calculated Answer
200 grams of 18K gold contains exactly 150.0 grams (4.8226 troy ounces) of pure fine gold, with an intrinsic scrap melt value of approximately $13,021.02 USD at $2,700/oz t.
4.8226 oz t
Primary Metric
150.0 g Fine Au
Secondary Metric
📐 Mathematical Formula & Step-by-Step Substitution
- Determine fineness ratio of 18K gold: 18 / 24 = 0.7500 (or 750.0‰ millesimal fineness).
- Multiply gross weight by fineness: 200 g × 0.7500 = 150.0 grams of fine elemental gold (Au).
- Convert grams to troy ounces (1 oz t = 31.1034768 g): 150.0 / 31.1034768 = 4.8226 troy ounces.
- Convert grams to tolas (1 tola = 11.6638 g): 150.0 / 11.6638 = 12.8603 tolas.
📊 Nearby Parameter Reference Table
| Gross Weight | Fine Gold (g) | Fine Gold (oz t) | Melt Value ($2,700/oz) |
|---|---|---|---|
| 100 g | 75.0 g | 2.4113 oz t | $6,510.51 |
| 160 g | 120.0 g | 3.8581 oz t | $10,416.87 |
| 200 g | 150.0 g | 4.8226 oz t | $13,021.02 |
| 240 g | 180.0 g | 5.7871 oz t | $15,625.17 |
| 300 g | 225.0 g | 7.2339 oz t | $19,531.53 |
| 400 g | 300.0 g | 9.6452 oz t | $26,042.04 |
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