How many troy ounces of fine gold are in 20 grams of 22K gold?
⚡ Instant Calculated Answer
20 grams of 22K gold contains exactly 18.333 grams (0.5894 troy ounces) of pure fine gold, with an intrinsic scrap melt value of approximately $1,591.38 USD at $2,700/oz t.
0.5894 oz t
Primary Metric
18.333 g Fine Au
Secondary Metric
📐 Mathematical Formula & Step-by-Step Substitution
- Determine fineness ratio of 22K gold: 22 / 24 = 0.9167 (or 916.7‰ millesimal fineness).
- Multiply gross weight by fineness: 20 g × 0.9167 = 18.333 grams of fine elemental gold (Au).
- Convert grams to troy ounces (1 oz t = 31.1034768 g): 18.333 / 31.1034768 = 0.5894 troy ounces.
- Convert grams to tolas (1 tola = 11.6638 g): 18.333 / 11.6638 = 1.5718 tolas.
📊 Nearby Parameter Reference Table
| Gross Weight | Fine Gold (g) | Fine Gold (oz t) | Melt Value ($2,700/oz) |
|---|---|---|---|
| 10 g | 9.167 g | 0.2947 oz t | $795.69 |
| 16 g | 14.667 g | 0.4716 oz t | $1,273.32 |
| 20 g | 18.333 g | 0.5894 oz t | $1,591.38 |
| 24 g | 22.0 g | 0.7073 oz t | $1,909.71 |
| 30 g | 27.5 g | 0.8841 oz t | $2,387.07 |
| 40 g | 36.667 g | 1.1789 oz t | $3,183.03 |
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