How many troy ounces of fine gold are in 20 grams of 21K gold?
⚡ Instant Calculated Answer
20 grams of 21K gold contains exactly 17.5 grams (0.5626 troy ounces) of pure fine gold, with an intrinsic scrap melt value of approximately $1,519.02 USD at $2,700/oz t.
0.5626 oz t
Primary Metric
17.5 g Fine Au
Secondary Metric
📐 Mathematical Formula & Step-by-Step Substitution
- Determine fineness ratio of 21K gold: 21 / 24 = 0.8750 (or 875.0‰ millesimal fineness).
- Multiply gross weight by fineness: 20 g × 0.8750 = 17.5 grams of fine elemental gold (Au).
- Convert grams to troy ounces (1 oz t = 31.1034768 g): 17.5 / 31.1034768 = 0.5626 troy ounces.
- Convert grams to tolas (1 tola = 11.6638 g): 17.5 / 11.6638 = 1.5004 tolas.
📊 Nearby Parameter Reference Table
| Gross Weight | Fine Gold (g) | Fine Gold (oz t) | Melt Value ($2,700/oz) |
|---|---|---|---|
| 10 g | 8.75 g | 0.2813 oz t | $759.51 |
| 16 g | 14.0 g | 0.4501 oz t | $1,215.27 |
| 20 g | 17.5 g | 0.5626 oz t | $1,519.02 |
| 24 g | 21.0 g | 0.6752 oz t | $1,823.04 |
| 30 g | 26.25 g | 0.844 oz t | $2,278.80 |
| 40 g | 35.0 g | 1.1253 oz t | $3,038.31 |
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