How many troy ounces of fine gold are in 20 grams of 18K gold?
⚡ Instant Calculated Answer
20 grams of 18K gold contains exactly 15.0 grams (0.4823 troy ounces) of pure fine gold, with an intrinsic scrap melt value of approximately $1,302.21 USD at $2,700/oz t.
0.4823 oz t
Primary Metric
15.0 g Fine Au
Secondary Metric
📐 Mathematical Formula & Step-by-Step Substitution
- Determine fineness ratio of 18K gold: 18 / 24 = 0.7500 (or 750.0‰ millesimal fineness).
- Multiply gross weight by fineness: 20 g × 0.7500 = 15.0 grams of fine elemental gold (Au).
- Convert grams to troy ounces (1 oz t = 31.1034768 g): 15.0 / 31.1034768 = 0.4823 troy ounces.
- Convert grams to tolas (1 tola = 11.6638 g): 15.0 / 11.6638 = 1.286 tolas.
📊 Nearby Parameter Reference Table
| Gross Weight | Fine Gold (g) | Fine Gold (oz t) | Melt Value ($2,700/oz) |
|---|---|---|---|
| 10 g | 7.5 g | 0.2411 oz t | $650.97 |
| 16 g | 12.0 g | 0.3858 oz t | $1,041.66 |
| 20 g | 15.0 g | 0.4823 oz t | $1,302.21 |
| 24 g | 18.0 g | 0.5787 oz t | $1,562.49 |
| 30 g | 22.5 g | 0.7234 oz t | $1,953.18 |
| 40 g | 30.0 g | 0.9645 oz t | $2,604.15 |
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