How many troy ounces of fine gold are in 20 grams of 14K gold?
⚡ Instant Calculated Answer
20 grams of 14K gold contains exactly 11.667 grams (0.3751 troy ounces) of pure fine gold, with an intrinsic scrap melt value of approximately $1,012.77 USD at $2,700/oz t.
0.3751 oz t
Primary Metric
11.667 g Fine Au
Secondary Metric
📐 Mathematical Formula & Step-by-Step Substitution
- Determine fineness ratio of 14K gold: 14 / 24 = 0.5833 (or 583.3‰ millesimal fineness).
- Multiply gross weight by fineness: 20 g × 0.5833 = 11.667 grams of fine elemental gold (Au).
- Convert grams to troy ounces (1 oz t = 31.1034768 g): 11.667 / 31.1034768 = 0.3751 troy ounces.
- Convert grams to tolas (1 tola = 11.6638 g): 11.667 / 11.6638 = 1.0003 tolas.
📊 Nearby Parameter Reference Table
| Gross Weight | Fine Gold (g) | Fine Gold (oz t) | Melt Value ($2,700/oz) |
|---|---|---|---|
| 10 g | 5.833 g | 0.1875 oz t | $506.25 |
| 16 g | 9.333 g | 0.3001 oz t | $810.27 |
| 20 g | 11.667 g | 0.3751 oz t | $1,012.77 |
| 24 g | 14.0 g | 0.4501 oz t | $1,215.27 |
| 30 g | 17.5 g | 0.5626 oz t | $1,519.02 |
| 40 g | 23.333 g | 0.7502 oz t | $2,025.54 |
Want to test custom numbers?
Launch the full interactive simulator pre-loaded with these exact calculation parameters.