How many troy ounces of fine gold are in 20 grams of 10K gold?
⚡ Instant Calculated Answer
20 grams of 10K gold contains exactly 8.333 grams (0.2679 troy ounces) of pure fine gold, with an intrinsic scrap melt value of approximately $723.33 USD at $2,700/oz t.
0.2679 oz t
Primary Metric
8.333 g Fine Au
Secondary Metric
📐 Mathematical Formula & Step-by-Step Substitution
- Determine fineness ratio of 10K gold: 10 / 24 = 0.4167 (or 416.7‰ millesimal fineness).
- Multiply gross weight by fineness: 20 g × 0.4167 = 8.333 grams of fine elemental gold (Au).
- Convert grams to troy ounces (1 oz t = 31.1034768 g): 8.333 / 31.1034768 = 0.2679 troy ounces.
- Convert grams to tolas (1 tola = 11.6638 g): 8.333 / 11.6638 = 0.7144 tolas.
📊 Nearby Parameter Reference Table
| Gross Weight | Fine Gold (g) | Fine Gold (oz t) | Melt Value ($2,700/oz) |
|---|---|---|---|
| 10 g | 4.167 g | 0.134 oz t | $361.80 |
| 16 g | 6.667 g | 0.2143 oz t | $578.61 |
| 20 g | 8.333 g | 0.2679 oz t | $723.33 |
| 24 g | 10.0 g | 0.3215 oz t | $868.05 |
| 30 g | 12.5 g | 0.4019 oz t | $1,085.13 |
| 40 g | 16.667 g | 0.5359 oz t | $1,446.93 |
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