How many Hertz and ticks per second is a 19,800 BPH watch movement?
⚡ Instant Calculated Answer
A 19,800 BPH mechanical movement operates at exactly 2.75 Hz (2.75 cycles per second) and produces 5.5 escapement ticks per second, with an oscillation period of 181.82 ms.
2.75 Hz
Primary Metric
5.5 ticks/sec
Secondary Metric
📐 Mathematical Formula & Step-by-Step Substitution
- Understand that 1 full balance wheel oscillation cycle equals 2 beats (one clockwise tick and one counter-clockwise tock).
- Convert beats per hour to full cycles per hour: 19,800 / 2 = 9,900 cycles/hour.
- Divide by 3,600 seconds per hour to calculate frequency in Hertz: 9,900 / 3,600 = 2.75 Hz.
- Calculate pallet fork impulses (ticks) per second: 19,800 / 3,600 = 5.5 ticks per second (period T = 181.82 ms).
📊 Nearby Parameter Reference Table
| Beat Rate (BPH) | Frequency (Hz) | Ticks / Second | Vibration Period |
|---|---|---|---|
| 12,600 BPH | 1.75 Hz | 3.5 / sec | 285.7 ms |
| 16,200 BPH | 2.25 Hz | 4.5 / sec | 222.2 ms |
| 19,800 BPH | 2.75 Hz | 5.5 / sec | 181.8 ms |
| 23,400 BPH | 3.25 Hz | 6.5 / sec | 153.8 ms |
| 27,000 BPH | 3.75 Hz | 7.5 / sec | 133.3 ms |
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