How many Hertz and ticks per second is a 18,000 BPH watch movement?
⚡ Instant Calculated Answer
A 18,000 BPH mechanical movement operates at exactly 2.5 Hz (2.5 cycles per second) and produces 5 escapement ticks per second, with an oscillation period of 200.0 ms.
2.5 Hz
Primary Metric
5 ticks/sec
Secondary Metric
📐 Mathematical Formula & Step-by-Step Substitution
- Understand that 1 full balance wheel oscillation cycle equals 2 beats (one clockwise tick and one counter-clockwise tock).
- Convert beats per hour to full cycles per hour: 18,000 / 2 = 9,000 cycles/hour.
- Divide by 3,600 seconds per hour to calculate frequency in Hertz: 9,000 / 3,600 = 2.5 Hz.
- Calculate pallet fork impulses (ticks) per second: 18,000 / 3,600 = 5 ticks per second (period T = 200.0 ms).
📊 Nearby Parameter Reference Table
| Beat Rate (BPH) | Frequency (Hz) | Ticks / Second | Vibration Period |
|---|---|---|---|
| 10,800 BPH | 1.5 Hz | 3.0 / sec | 333.3 ms |
| 14,400 BPH | 2.0 Hz | 4.0 / sec | 250.0 ms |
| 18,000 BPH | 2.5 Hz | 5.0 / sec | 200.0 ms |
| 21,600 BPH | 3.0 Hz | 6.0 / sec | 166.7 ms |
| 25,200 BPH | 3.5 Hz | 7.0 / sec | 142.9 ms |
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