How many troy ounces of fine gold are in 150 grams of 21K gold?
⚡ Instant Calculated Answer
150 grams of 21K gold contains exactly 131.25 grams (4.2198 troy ounces) of pure fine gold, with an intrinsic scrap melt value of approximately $11,393.46 USD at $2,700/oz t.
4.2198 oz t
Primary Metric
131.25 g Fine Au
Secondary Metric
📐 Mathematical Formula & Step-by-Step Substitution
- Determine fineness ratio of 21K gold: 21 / 24 = 0.8750 (or 875.0‰ millesimal fineness).
- Multiply gross weight by fineness: 150 g × 0.8750 = 131.25 grams of fine elemental gold (Au).
- Convert grams to troy ounces (1 oz t = 31.1034768 g): 131.25 / 31.1034768 = 4.2198 troy ounces.
- Convert grams to tolas (1 tola = 11.6638 g): 131.25 / 11.6638 = 11.2528 tolas.
📊 Nearby Parameter Reference Table
| Gross Weight | Fine Gold (g) | Fine Gold (oz t) | Melt Value ($2,700/oz) |
|---|---|---|---|
| 75 g | 65.625 g | 2.1099 oz t | $5,696.73 |
| 120 g | 105.0 g | 3.3758 oz t | $9,114.66 |
| 150 g | 131.25 g | 4.2198 oz t | $11,393.46 |
| 180 g | 157.5 g | 5.0637 oz t | $13,671.99 |
| 225 g | 196.875 g | 6.3297 oz t | $17,090.19 |
| 300 g | 262.5 g | 8.4396 oz t | $22,786.92 |
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