How many troy ounces of fine gold are in 150 grams of 10K gold?
⚡ Instant Calculated Answer
150 grams of 10K gold contains exactly 62.5 grams (2.0094 troy ounces) of pure fine gold, with an intrinsic scrap melt value of approximately $5,425.38 USD at $2,700/oz t.
2.0094 oz t
Primary Metric
62.5 g Fine Au
Secondary Metric
📐 Mathematical Formula & Step-by-Step Substitution
- Determine fineness ratio of 10K gold: 10 / 24 = 0.4167 (or 416.7‰ millesimal fineness).
- Multiply gross weight by fineness: 150 g × 0.4167 = 62.5 grams of fine elemental gold (Au).
- Convert grams to troy ounces (1 oz t = 31.1034768 g): 62.5 / 31.1034768 = 2.0094 troy ounces.
- Convert grams to tolas (1 tola = 11.6638 g): 62.5 / 11.6638 = 5.3585 tolas.
📊 Nearby Parameter Reference Table
| Gross Weight | Fine Gold (g) | Fine Gold (oz t) | Melt Value ($2,700/oz) |
|---|---|---|---|
| 75 g | 31.25 g | 1.0047 oz t | $2,712.69 |
| 120 g | 50.0 g | 1.6075 oz t | $4,340.25 |
| 150 g | 62.5 g | 2.0094 oz t | $5,425.38 |
| 180 g | 75.0 g | 2.4113 oz t | $6,510.51 |
| 225 g | 93.75 g | 3.0141 oz t | $8,138.07 |
| 300 g | 125.0 g | 4.0188 oz t | $10,850.76 |
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