How many troy ounces of fine gold are in 15 grams of 22K gold?
⚡ Instant Calculated Answer
15 grams of 22K gold contains exactly 13.75 grams (0.4421 troy ounces) of pure fine gold, with an intrinsic scrap melt value of approximately $1,193.67 USD at $2,700/oz t.
0.4421 oz t
Primary Metric
13.75 g Fine Au
Secondary Metric
📐 Mathematical Formula & Step-by-Step Substitution
- Determine fineness ratio of 22K gold: 22 / 24 = 0.9167 (or 916.7‰ millesimal fineness).
- Multiply gross weight by fineness: 15 g × 0.9167 = 13.75 grams of fine elemental gold (Au).
- Convert grams to troy ounces (1 oz t = 31.1034768 g): 13.75 / 31.1034768 = 0.4421 troy ounces.
- Convert grams to tolas (1 tola = 11.6638 g): 13.75 / 11.6638 = 1.1789 tolas.
📊 Nearby Parameter Reference Table
| Gross Weight | Fine Gold (g) | Fine Gold (oz t) | Melt Value ($2,700/oz) |
|---|---|---|---|
| 7.5 g | 6.875 g | 0.221 oz t | $596.70 |
| 12 g | 11.0 g | 0.3537 oz t | $954.99 |
| 15 g | 13.75 g | 0.4421 oz t | $1,193.67 |
| 18 g | 16.5 g | 0.5305 oz t | $1,432.35 |
| 22.5 g | 20.625 g | 0.6631 oz t | $1,790.37 |
| 30 g | 27.5 g | 0.8841 oz t | $2,387.07 |
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