How many troy ounces of fine gold are in 15 grams of 21K gold?
⚡ Instant Calculated Answer
15 grams of 21K gold contains exactly 13.125 grams (0.422 troy ounces) of pure fine gold, with an intrinsic scrap melt value of approximately $1,139.40 USD at $2,700/oz t.
0.422 oz t
Primary Metric
13.125 g Fine Au
Secondary Metric
📐 Mathematical Formula & Step-by-Step Substitution
- Determine fineness ratio of 21K gold: 21 / 24 = 0.8750 (or 875.0‰ millesimal fineness).
- Multiply gross weight by fineness: 15 g × 0.8750 = 13.125 grams of fine elemental gold (Au).
- Convert grams to troy ounces (1 oz t = 31.1034768 g): 13.125 / 31.1034768 = 0.422 troy ounces.
- Convert grams to tolas (1 tola = 11.6638 g): 13.125 / 11.6638 = 1.1253 tolas.
📊 Nearby Parameter Reference Table
| Gross Weight | Fine Gold (g) | Fine Gold (oz t) | Melt Value ($2,700/oz) |
|---|---|---|---|
| 7.5 g | 6.562 g | 0.211 oz t | $569.70 |
| 12 g | 10.5 g | 0.3376 oz t | $911.52 |
| 15 g | 13.125 g | 0.422 oz t | $1,139.40 |
| 18 g | 15.75 g | 0.5064 oz t | $1,367.28 |
| 22.5 g | 19.688 g | 0.633 oz t | $1,709.10 |
| 30 g | 26.25 g | 0.844 oz t | $2,278.80 |
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