How many troy ounces of fine gold are in 15 grams of 18K gold?
⚡ Instant Calculated Answer
15 grams of 18K gold contains exactly 11.25 grams (0.3617 troy ounces) of pure fine gold, with an intrinsic scrap melt value of approximately $976.59 USD at $2,700/oz t.
0.3617 oz t
Primary Metric
11.25 g Fine Au
Secondary Metric
📐 Mathematical Formula & Step-by-Step Substitution
- Determine fineness ratio of 18K gold: 18 / 24 = 0.7500 (or 750.0‰ millesimal fineness).
- Multiply gross weight by fineness: 15 g × 0.7500 = 11.25 grams of fine elemental gold (Au).
- Convert grams to troy ounces (1 oz t = 31.1034768 g): 11.25 / 31.1034768 = 0.3617 troy ounces.
- Convert grams to tolas (1 tola = 11.6638 g): 11.25 / 11.6638 = 0.9645 tolas.
📊 Nearby Parameter Reference Table
| Gross Weight | Fine Gold (g) | Fine Gold (oz t) | Melt Value ($2,700/oz) |
|---|---|---|---|
| 7.5 g | 5.625 g | 0.1808 oz t | $488.16 |
| 12 g | 9.0 g | 0.2894 oz t | $781.38 |
| 15 g | 11.25 g | 0.3617 oz t | $976.59 |
| 18 g | 13.5 g | 0.434 oz t | $1,171.80 |
| 22.5 g | 16.875 g | 0.5425 oz t | $1,464.75 |
| 30 g | 22.5 g | 0.7234 oz t | $1,953.18 |
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