How many troy ounces of fine gold are in 15 grams of 10K gold?
⚡ Instant Calculated Answer
15 grams of 10K gold contains exactly 6.25 grams (0.2009 troy ounces) of pure fine gold, with an intrinsic scrap melt value of approximately $542.43 USD at $2,700/oz t.
0.2009 oz t
Primary Metric
6.25 g Fine Au
Secondary Metric
📐 Mathematical Formula & Step-by-Step Substitution
- Determine fineness ratio of 10K gold: 10 / 24 = 0.4167 (or 416.7‰ millesimal fineness).
- Multiply gross weight by fineness: 15 g × 0.4167 = 6.25 grams of fine elemental gold (Au).
- Convert grams to troy ounces (1 oz t = 31.1034768 g): 6.25 / 31.1034768 = 0.2009 troy ounces.
- Convert grams to tolas (1 tola = 11.6638 g): 6.25 / 11.6638 = 0.5358 tolas.
📊 Nearby Parameter Reference Table
| Gross Weight | Fine Gold (g) | Fine Gold (oz t) | Melt Value ($2,700/oz) |
|---|---|---|---|
| 7.5 g | 3.125 g | 0.1005 oz t | $271.35 |
| 12 g | 5.0 g | 0.1608 oz t | $434.16 |
| 15 g | 6.25 g | 0.2009 oz t | $542.43 |
| 18 g | 7.5 g | 0.2411 oz t | $650.97 |
| 22.5 g | 9.375 g | 0.3014 oz t | $813.78 |
| 30 g | 12.5 g | 0.4019 oz t | $1,085.13 |
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