Horology & Precision Mechanics

How many Hertz and ticks per second is a 14,400 BPH watch movement?

⚡ Instant Calculated Answer

A 14,400 BPH mechanical movement operates at exactly 2.0 Hz (2.0 cycles per second) and produces 4 escapement ticks per second, with an oscillation period of 250.0 ms.

2.0 Hz Primary Metric
4 ticks/sec Secondary Metric

📐 Mathematical Formula & Step-by-Step Substitution

\[ f_{Hz} = \frac{\text{BPH}}{7200} = \frac{14400}{7200} = 2.0 \text{ Hz} \quad \text{and} \quad \text{TPS} = \frac{14400}{3600} = 4 \]
f_Hz = 14400 / 7200 = 2.0 Hz ; Ticks_per_sec = 14400 / 3600 = 4
  1. Understand that 1 full balance wheel oscillation cycle equals 2 beats (one clockwise tick and one counter-clockwise tock).
  2. Convert beats per hour to full cycles per hour: 14,400 / 2 = 7,200 cycles/hour.
  3. Divide by 3,600 seconds per hour to calculate frequency in Hertz: 7,200 / 3,600 = 2.0 Hz.
  4. Calculate pallet fork impulses (ticks) per second: 14,400 / 3,600 = 4 ticks per second (period T = 250.0 ms).

📊 Nearby Parameter Reference Table

Beat Rate (BPH) Frequency (Hz) Ticks / Second Vibration Period
7,200 BPH 1.0 Hz 2.0 / sec 500.0 ms
10,800 BPH 1.5 Hz 3.0 / sec 333.3 ms
14,400 BPH 2.0 Hz 4.0 / sec 250.0 ms
18,000 BPH 2.5 Hz 5.0 / sec 200.0 ms
21,600 BPH 3.0 Hz 6.0 / sec 166.7 ms
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