How many troy ounces of fine gold are in 1000 grams of 21K gold?
⚡ Instant Calculated Answer
1000 grams of 21K gold contains exactly 875.0 grams (28.1319 troy ounces) of pure fine gold, with an intrinsic scrap melt value of approximately $75,956.13 USD at $2,700/oz t.
28.1319 oz t
Primary Metric
875.0 g Fine Au
Secondary Metric
📐 Mathematical Formula & Step-by-Step Substitution
- Determine fineness ratio of 21K gold: 21 / 24 = 0.8750 (or 875.0‰ millesimal fineness).
- Multiply gross weight by fineness: 1000 g × 0.8750 = 875.0 grams of fine elemental gold (Au).
- Convert grams to troy ounces (1 oz t = 31.1034768 g): 875.0 / 31.1034768 = 28.1319 troy ounces.
- Convert grams to tolas (1 tola = 11.6638 g): 875.0 / 11.6638 = 75.0184 tolas.
📊 Nearby Parameter Reference Table
| Gross Weight | Fine Gold (g) | Fine Gold (oz t) | Melt Value ($2,700/oz) |
|---|---|---|---|
| 500 g | 437.5 g | 14.066 oz t | $37,978.20 |
| 800 g | 700.0 g | 22.5055 oz t | $60,764.85 |
| 1000 g | 875.0 g | 28.1319 oz t | $75,956.13 |
| 1200 g | 1050.0 g | 33.7583 oz t | $91,147.41 |
| 1500 g | 1312.5 g | 42.1979 oz t | $113,934.33 |
| 2000 g | 1750.0 g | 56.2638 oz t | $151,912.26 |
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