How many troy ounces of fine gold are in 10 grams of 10K gold?
⚡ Instant Calculated Answer
10 grams of 10K gold contains exactly 4.167 grams (0.134 troy ounces) of pure fine gold, with an intrinsic scrap melt value of approximately $361.80 USD at $2,700/oz t.
0.134 oz t
Primary Metric
4.167 g Fine Au
Secondary Metric
📐 Mathematical Formula & Step-by-Step Substitution
- Determine fineness ratio of 10K gold: 10 / 24 = 0.4167 (or 416.7‰ millesimal fineness).
- Multiply gross weight by fineness: 10 g × 0.4167 = 4.167 grams of fine elemental gold (Au).
- Convert grams to troy ounces (1 oz t = 31.1034768 g): 4.167 / 31.1034768 = 0.134 troy ounces.
- Convert grams to tolas (1 tola = 11.6638 g): 4.167 / 11.6638 = 0.3573 tolas.
📊 Nearby Parameter Reference Table
| Gross Weight | Fine Gold (g) | Fine Gold (oz t) | Melt Value ($2,700/oz) |
|---|---|---|---|
| 5 g | 2.083 g | 0.067 oz t | $180.90 |
| 8 g | 3.333 g | 0.1072 oz t | $289.44 |
| 10 g | 4.167 g | 0.134 oz t | $361.80 |
| 12 g | 5.0 g | 0.1608 oz t | $434.16 |
| 15 g | 6.25 g | 0.2009 oz t | $542.43 |
| 20 g | 8.333 g | 0.2679 oz t | $723.33 |
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